Volumetric Calculations

Describe the fundamental of volumetric analysis.

A certain aqueous solution of ${\mathrm{FeCl}}_3$ (formula mass $=162$) has a density of $1.1 \mathrm{g}/\mathrm{mL}$ and contains $20.0\% {\mathrm{FeCl}}_3$. Calculate the molar concentration of this solution.

$1.1 \mathrm{g} {\mathrm{CH}}_3{\left({\mathrm{CH}}_2\right)}_{\mathrm{n}}\mathrm{COOH}$ was burnt in excess of air and the resultant gases $\left({\mathrm{CO}}_2+{\mathrm{H}}_2\mathrm{O}\right)$ were passed through a solution of $\mathrm{NaOH}$. The resulting solution is divided into two equal parts. One part required $75$m.e. of $\mathrm{HCl}$ for neutralisation using phenolphthalein as indicator. The other part required $100$ m.e. of $\mathrm{HCl}$ using methyl orange as indicator. Find $\mathrm{n}$.

A quantity of $50 \mathrm{g}$ of water is saturated with $\mathrm{HCl}$ gas to get $75 \mathrm{mL}$ of solution containing $40\% \mathrm{HCl}$ by mass. The density of solution formed is?

A solution of glucose in water is labelled as $20\% (\mathrm{w}/\mathrm{W})$. The density of the solution is $1.20 \mathrm{g} {\mathrm{mL}}^{-1}$. Calculate molality.

Commercially available concentrated hydrofluoric acid contains $38\% \mathrm{HF}$ by volume$\left(\raisebox{1ex}{$\mathrm{v}$}\!\left/ \!\raisebox{-1ex}{$\mathrm{V}$}\right.\%\right)$. The density of $\mathrm{HF}$ is $1.19 \mathrm{g} {\mathrm{ml}}^{-1}$ and density of solution is $1.39 \mathrm{g} {\mathrm{ml}}^{-1}$. What is the molality of this solution?
 

Commercially available concentrated hydrofluoric acid contains $48\% \mathrm{HF}$ by volume$\left(\raisebox{1ex}{$\mathrm{v}$}\!\left/ \!\raisebox{-1ex}{$\mathrm{V}$}\right.\%\right)$. What is the molality of this solution? The density of $\mathrm{HF}$ is $1.19 \mathrm{g} {\mathrm{ml}}^{-1}$ and density of solution is $1.39 \mathrm{g} {\mathrm{ml}}^{-1}$.
 

Commercially available concentrated hydrofluoric acid contains $48\% \mathrm{HF}$ by volume$\left(\raisebox{1ex}{$\mathrm{v}$}\!\left/ \!\raisebox{-1ex}{$\mathrm{V}$}\right.\%\right)$. What is the molality of this solution? The density of $\mathrm{HF}$ is $1.19 \mathrm{g} {\mathrm{ml}}^{-1}$ and density of solution is $1.39 \mathrm{g} {\mathrm{ml}}^{-1}$.
 

A solution of glucose in water is labelled as $20\% (\mathrm{w}/\mathrm{V})$. The density of the solution is $1.20 \mathrm{g} {\mathrm{mL}}^{-1}$. The molality of the solution is 

A solution of glucose in water is labelled as $10\% (\mathrm{w}/\mathrm{V})$. The density of the solution is $1.20 \mathrm{g} {\mathrm{mL}}^{-1}$. The molality of the solution is 

Commercially available concentrated hydrochloric acid contains $28\% \mathrm{HCl}$ by volume$\left(\mathrm{v}/\mathrm{V}\%\right)$. The density of $\mathrm{HCl}$ is $3.131 \mathrm{g} {\mathrm{ml}}^{-1}$. The molarity of the solution is $\approx 24 \mathrm{M}$
 

Commercially available concentrated hydrochloric acid contains $28\% \mathrm{HCl}$ by volume$\left(\mathrm{v}/\mathrm{V}\%\right)$. The density of $\mathrm{HCl}$ is $3.131 \mathrm{g} {\mathrm{ml}}^{-1}$. The molarity of the solution is
 

Commercially available concentrated hydrochloric acid contains $28\% \mathrm{HCl}$ by volume. What is the molarity of this solution? The density of $\mathrm{HCl}$ is $3.131 \mathrm{g} {\mathrm{ml}}^{-1}$.
 

(Weight/weight)% $= \mathrm{d} \times$ (volume/weight)%

A $20\% (\mathrm{v}/\mathrm{W})$ solution has a density of $1.5 \mathrm{g}/\mathrm{ml}$. The weight percentage$(\mathrm{w}/\mathrm{W}\%)$ of the solution is $30\%$.

A $15\% (\mathrm{v}/\mathrm{W})$ solution has a density of $1.5 \mathrm{g}/\mathrm{ml}$. Calculates the weight percentage$(\mathrm{w}/\mathrm{W}\%)$ of the solution.

Commercially available concentrated hydrofluoric acid contains $38\% \mathrm{HF}$ by volume$\left(\raisebox{1ex}{$\mathrm{v}$}\!\left/ \!\raisebox{-1ex}{$\mathrm{V}$}\right.\%\right)$. What is the molality of this solution? The density of $\mathrm{HF}$ is $1.19 \mathrm{g} {\mathrm{ml}}^{-1}$ and density of solution is $1.39 \mathrm{g} {\mathrm{ml}}^{-1}$.
 

A solution of glucose in water is labelled as $10\% (\mathrm{w}/\mathrm{V})$. The density of the solution is $1.20 \mathrm{g} {\mathrm{mL}}^{-1}$. Calculate molality.